-3m(m-4)=m+4

Solution for -3m(m-4)=m+4 equation:

-3m(m-4)=m+4

We move all terms to the left:

-3m(m-4)-(m+4)=0

We multiply parentheses

-3m^2+12m-(m+4)=0

We get rid of parentheses

-3m^2+12m-m-4=0

We add all the numbers together, and all the variables

-3m^2+11m-4=0

a = -3; b = 11; c = -4;
Δ = b2-4ac
Δ = 112-4·(-3)·(-4)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{73}}{2*-3}=\frac{-11-\sqrt{73}}{-6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{73}}{2*-3}=\frac{-11+\sqrt{73}}{-6}
$