-3k-9/(3k-5)=1/6

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Solution for -3k-9/(3k-5)=1/6 equation:


D( k )

3*k-5 = 0

3*k-5 = 0

3*k-5 = 0

3*k-5 = 0 // + 5

3*k = 5 // : 3

k = 5/3

k in (-oo:5/3) U (5/3:+oo)

-(9/(3*k-5))-3*k = 1/6 // - 1/6

-(9/(3*k-5))-3*k-(1/6) = 0

-9*(3*k-5)^-1-3*k-1/6 = 0

-9/(3*k-5)-3*k-1/6 = 0

(-9*6)/(6*(3*k-5))+(-3*6*k*(3*k-5))/(6*(3*k-5))+(-1*(3*k-5))/(6*(3*k-5)) = 0

-3*6*k*(3*k-5)-1*(3*k-5)-9*6 = 0

90*k-54*k^2-3*k-54+5 = 0

87*k-54*k^2-49 = 0

87*k-54*k^2-49 = 0

87*k-54*k^2-49 = 0

DELTA = 87^2-(-54*(-49)*4)

DELTA = -3015

DELTA < 0

1 = 0

1/(6*(3*k-5)) = 0

1/(6*(3*k-5)) = 0 // * 6*(3*k-5)

1 = 0

k belongs to the empty set

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