-3cos(2x)/2

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Solution for -3cos(2x)/2 equation: 


x in (-oo:+oo)

(-3*cos(2*x))/2 = 0

(-3*cos(2*x))/2 = 0 // * 2

-3*cos(2*x) = 0

cos(2*x) = 0

cos(2*x) = 0  <=>  2*x = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

2*x-t_1 = 0

2*x-t_1 = 0 // + t_1

2*x = t_1 // : 2

x = t_1/2

x = pi*k_1+pi/2/2 i k_1 należy do I

-3*cos(2*x) = 0  <=>  -3 = 0 or -3*cos(2*x) = 0  <=>  cos(2*x) = 0

x = pi*k_1+pi/2/2

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