-3c-4+7c=16+2c

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Solution for -3c-4+7c=16+2c equation: 



-3c-4+7c=16+2c

We move all terms to the left:

-3c-4+7c-(16+2c)=0

We add all the numbers together, and all the variables

-3c+7c-(2c+16)-4=0

We add all the numbers together, and all the variables

4c-(2c+16)-4=0

We get rid of parentheses

4c-2c-16-4=0

We add all the numbers together, and all the variables

2c-20=0

We move all terms containing c to the left, all other terms to the right

2c=20

c=20/2

c=10

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