-3c-(2c+1)+(c+3)=2

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Solution for -3c-(2c+1)+(c+3)=2 equation: 



-3c-(2c+1)+(c+3)=2

We move all terms to the left:

-3c-(2c+1)+(c+3)-(2)=0

We get rid of parentheses

-3c-2c+c-1+3-2=0

We add all the numbers together, and all the variables

-4c=0

c=0/-4

c=0

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