-3b+5(b+2)=4b-(3b+5)

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Solution for -3b+5(b+2)=4b-(3b+5) equation: 



-3b+5(b+2)=4b-(3b+5)

We move all terms to the left:

-3b+5(b+2)-(4b-(3b+5))=0

We multiply parentheses

-3b+5b-(4b-(3b+5))+10=0



We calculate terms in parentheses: -(4b-(3b+5)), so:

4b-(3b+5)

We get rid of parentheses

4b-3b-5

We add all the numbers together, and all the variables

b-5

Back to the equation:

-(b-5)



We add all the numbers together, and all the variables

2b-(b-5)+10=0

We get rid of parentheses

2b-b+5+10=0

We add all the numbers together, and all the variables

b+15=0

We move all terms containing b to the left, all other terms to the right

b=-15

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