-3b+1=b-5-2b

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Solution for -3b+1=b-5-2b equation: 



-3b+1=b-5-2b

We move all terms to the left:

-3b+1-(b-5-2b)=0

We add all the numbers together, and all the variables

-3b-(-1b-5)+1=0

We get rid of parentheses

-3b+1b+5+1=0

We add all the numbers together, and all the variables

-2b+6=0

We move all terms containing b to the left, all other terms to the right

-2b=-6

b=-6/-2

b=+3

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