-3b+10=2(3-b)

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Solution for -3b+10=2(3-b) equation: 



-3b+10=2(3-b)

We move all terms to the left:

-3b+10-(2(3-b))=0

We add all the numbers together, and all the variables

-3b-(2(-1b+3))+10=0



We calculate terms in parentheses: -(2(-1b+3)), so:

2(-1b+3)

We multiply parentheses

-2b+6

Back to the equation:

-(-2b+6)



We get rid of parentheses

-3b+2b-6+10=0

We add all the numbers together, and all the variables

-1b+4=0

We move all terms containing b to the left, all other terms to the right

-b=-4

b=-4/-1

b=+4

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