-3a+1=3(-2a+1)-5

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Solution for -3a+1=3(-2a+1)-5 equation: 



-3a+1=3(-2a+1)-5

We move all terms to the left:

-3a+1-(3(-2a+1)-5)=0



We calculate terms in parentheses: -(3(-2a+1)-5), so:

3(-2a+1)-5

We multiply parentheses

-6a+3-5

We add all the numbers together, and all the variables

-6a-2

Back to the equation:

-(-6a-2)



We get rid of parentheses

-3a+6a+2+1=0

We add all the numbers together, and all the variables

3a+3=0

We move all terms containing a to the left, all other terms to the right

3a=-3

a=-3/3

a=-1

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