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-3=2+x2
We move all terms to the left:
-3-(2+x2)=0
We add all the numbers together, and all the variables
-(+x^2+2)-3=0
We get rid of parentheses
-x^2-2-3=0
We add all the numbers together, and all the variables
-1x^2-5=0
a = -1; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-1)·(-5)
Δ = -20
Delta is less than zero, so there is no solution for the equation
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