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-3=-x2-5x+7.
We move all terms to the left:
-3-(-x2-5x+7.)=0
We add all the numbers together, and all the variables
-(-1x^2-5x+7.)-3=0
We get rid of parentheses
1x^2+5x-7.-3=0
We add all the numbers together, and all the variables
x^2+5x-10=0
a = 1; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·1·(-10)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{65}}{2*1}=\frac{-5-\sqrt{65}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{65}}{2*1}=\frac{-5+\sqrt{65}}{2} $
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