-3=(n/3)-7

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Solution for -3=(n/3)-7 equation: 



-3=(n/3)-7

We move all terms to the left:

-3-((n/3)-7)=0

We add all the numbers together, and all the variables

-((+n/3)-7)-3=0

We multiply all the terms by the denominator


-((+n-3*3)-7)=0



We calculate terms in parentheses: -((+n-3*3)-7), so:

(+n-3*3)-7

We add all the numbers together, and all the variables

(n-9)-7

We get rid of parentheses

n-9-7

We add all the numbers together, and all the variables

n-16

Back to the equation:

-(n-16)



We get rid of parentheses

-n+16=0

We add all the numbers together, and all the variables

-1n+16=0

We move all terms containing n to the left, all other terms to the right

-n=-16

n=-16/-1

n=+16

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