-3=(3/9)+b

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Solution for -3=(3/9)+b equation: 



-3=(3/9)+b

We move all terms to the left:

-3-((3/9)+b)=0



Domain of the equation: 9)+b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-((+3/9)+b)-3=0

We multiply all the terms by the denominator


-((+3-3*9)+b)=0



We calculate terms in parentheses: -((+3-3*9)+b), so:

(+3-3*9)+b

determiningTheFunctionDomain
b+(+3-3*9)

We add all the numbers together, and all the variables

b+(-24)

We add all the numbers together, and all the variables

b-24

Back to the equation:

-(b-24)



We get rid of parentheses

-b+24=0

We add all the numbers together, and all the variables

-1b+24=0

We move all terms containing b to the left, all other terms to the right

-b=-24

b=-24/-1

b=+24

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