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-3=(1/6)v
We move all terms to the left:
-3-((1/6)v)=0
Domain of the equation: 6)v)!=0We add all the numbers together, and all the variables
v!=0/1
v!=0
v∈R
-((+1/6)v)-3=0
We multiply all the terms by the denominator
-((+1-3*6)v)=0
We calculate terms in parentheses: -((+1-3*6)v), so:We get rid of parentheses
(+1-3*6)v
We add all the numbers together, and all the variables
(-17)v
We multiply parentheses
-17v
Back to the equation:
-(-17v)
17v=0
v=0/17
v=0
Równanie nie ma rozwiązania
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