-38x2+108x+225=0

Solution for -38x2+108x+225=0 equation:

-38x^2+108x+225=0

a = -38; b = 108; c = +225;
Δ = b2-4ac
Δ = 1082-4·(-38)·225
Δ = 45864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45864}=\sqrt{1764*26}=\sqrt{1764}*\sqrt{26}=42\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-42\sqrt{26}}{2*-38}=\frac{-108-42\sqrt{26}}{-76}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+42\sqrt{26}}{2*-38}=\frac{-108+42\sqrt{26}}{-76}
$