-38=2(2x-5)+4(x+3)

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Solution for -38=2(2x-5)+4(x+3) equation: 



-38=2(2x-5)+4(x+3)

We move all terms to the left:

-38-(2(2x-5)+4(x+3))=0



We calculate terms in parentheses: -(2(2x-5)+4(x+3)), so:

2(2x-5)+4(x+3)

We multiply parentheses

4x+4x-10+12

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We get rid of parentheses

-8x-2-38=0

We add all the numbers together, and all the variables

-8x-40=0

We move all terms containing x to the left, all other terms to the right

-8x=40

x=40/-8

x=-5

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