-37+4y+5=2(3y-5)-4

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Solution for -37+4y+5=2(3y-5)-4 equation: 



-37+4y+5=2(3y-5)-4

We move all terms to the left:

-37+4y+5-(2(3y-5)-4)=0

We add all the numbers together, and all the variables

4y-(2(3y-5)-4)-32=0



We calculate terms in parentheses: -(2(3y-5)-4), so:

2(3y-5)-4

We multiply parentheses

6y-10-4

We add all the numbers together, and all the variables

6y-14

Back to the equation:

-(6y-14)



We get rid of parentheses

4y-6y+14-32=0

We add all the numbers together, and all the variables

-2y-18=0

We move all terms containing y to the left, all other terms to the right

-2y=18

y=18/-2

y=-9

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