-35x2-41x-12=

Solution for -35x2-41x-12= equation:

-35x^2-41x-12=

We move all terms to the left:

-35x^2-41x-12-()=0

We add all the numbers together, and all the variables

-35x^2-41x=0

a = -35; b = -41; c = 0;
Δ = b2-4ac
Δ = -412-4·(-35)·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-41}{2*-35}=\frac{0}{-70}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+41}{2*-35}=\frac{82}{-70}
=-1+6/35
$