-35=x-4x+10(x+1)-2x(x+1)

Solution for -35=x-4x+10(x+1)-2x(x+1) equation:

-35=x-4x+10(x+1)-2x(x+1)

We move all terms to the left:

-35-(x-4x+10(x+1)-2x(x+1))=0


We calculate terms in parentheses: -(x-4x+10(x+1)-2x(x+1)), so:

x-4x+10(x+1)-2x(x+1)

We add all the numbers together, and all the variables

-3x+10(x+1)-2x(x+1)

We multiply parentheses

-2x^2-3x+10x-2x+10

We add all the numbers together, and all the variables

-2x^2+5x+10

Back to the equation:

-(-2x^2+5x+10)


We get rid of parentheses

2x^2-5x-10-35=0

We add all the numbers together, and all the variables

2x^2-5x-45=0

a = 2; b = -5; c = -45;
Δ = b2-4ac
Δ = -52-4·2·(-45)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{385}}{2*2}=\frac{5-\sqrt{385}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{385}}{2*2}=\frac{5+\sqrt{385}}{4}
$