-35=2y+3(y+5)

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Solution for -35=2y+3(y+5) equation: 



-35=2y+3(y+5)

We move all terms to the left:

-35-(2y+3(y+5))=0



We calculate terms in parentheses: -(2y+3(y+5)), so:

2y+3(y+5)

We multiply parentheses

2y+3y+15

We add all the numbers together, and all the variables

5y+15

Back to the equation:

-(5y+15)



We get rid of parentheses

-5y-15-35=0

We add all the numbers together, and all the variables

-5y-50=0

We move all terms containing y to the left, all other terms to the right

-5y=50

y=50/-5

y=-10

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