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-33+4x=5+3(4-2x)
We move all terms to the left:
-33+4x-(5+3(4-2x))=0
We add all the numbers together, and all the variables
4x-(5+3(-2x+4))-33=0
We calculate terms in parentheses: -(5+3(-2x+4)), so:We get rid of parentheses
5+3(-2x+4)
determiningTheFunctionDomain 3(-2x+4)+5
We multiply parentheses
-6x+12+5
We add all the numbers together, and all the variables
-6x+17
Back to the equation:
-(-6x+17)
4x+6x-17-33=0
We add all the numbers together, and all the variables
10x-50=0
We move all terms containing x to the left, all other terms to the right
10x=50
x=50/10
x=5
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