-32=6(v-5)-8v

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Solution for -32=6(v-5)-8v equation: 



-32=6(v-5)-8v

We move all terms to the left:

-32-(6(v-5)-8v)=0



We calculate terms in parentheses: -(6(v-5)-8v), so:

6(v-5)-8v

We add all the numbers together, and all the variables

-8v+6(v-5)

We multiply parentheses

-8v+6v-30

We add all the numbers together, and all the variables

-2v-30

Back to the equation:

-(-2v-30)



We get rid of parentheses

2v+30-32=0

We add all the numbers together, and all the variables

2v-2=0

We move all terms containing v to the left, all other terms to the right

2v=2

v=2/2

v=1

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