-32=3/5f=17

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Solution for -32=3/5f=17 equation:



-32=3/5f=17
We move all terms to the left:
-32-(3/5f)=0
Domain of the equation: 5f)!=0
f!=0/1
f!=0
f∈R
We add all the numbers together, and all the variables
-(+3/5f)-32=0
We get rid of parentheses
-3/5f-32=0
We multiply all the terms by the denominator
-32*5f-3=0
Wy multiply elements
-160f-3=0
We move all terms containing f to the left, all other terms to the right
-160f=3
f=3/-160
f=-3/160

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