-32=2(y-7)-5y

Solution for -32=2(y-7)-5y equation:

-32=2(y-7)-5y

We move all terms to the left:

-32-(2(y-7)-5y)=0


We calculate terms in parentheses: -(2(y-7)-5y), so:

2(y-7)-5y

We add all the numbers together, and all the variables

-5y+2(y-7)

We multiply parentheses

-5y+2y-14

We add all the numbers together, and all the variables

-3y-14

Back to the equation:

-(-3y-14)


We get rid of parentheses

3y+14-32=0

We add all the numbers together, and all the variables

3y-18=0

We move all terms containing y to the left, all other terms to the right

3y=18

y=18/3

y=6