-32=2(u-7)=5u

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Solution for -32=2(u-7)=5u equation:



-32=2(u-7)=5u
We move all terms to the left:
-32-(2(u-7))=0
We calculate terms in parentheses: -(2(u-7)), so:
2(u-7)
We multiply parentheses
2u-14
Back to the equation:
-(2u-14)
We get rid of parentheses
-2u+14-32=0
We add all the numbers together, and all the variables
-2u-18=0
We move all terms containing u to the left, all other terms to the right
-2u=18
u=18/-2
u=-9

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