-32=-3+7x+(3x-2)

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Solution for -32=-3+7x+(3x-2) equation: 



-32=-3+7x+(3x-2)

We move all terms to the left:

-32-(-3+7x+(3x-2))=0



We calculate terms in parentheses: -(-3+7x+(3x-2)), so:

-3+7x+(3x-2)

determiningTheFunctionDomain
7x+(3x-2)-3

We get rid of parentheses

7x+3x-2-3

We add all the numbers together, and all the variables

10x-5

Back to the equation:

-(10x-5)



We get rid of parentheses

-10x+5-32=0

We add all the numbers together, and all the variables

-10x-27=0

We move all terms containing x to the left, all other terms to the right

-10x=27

x=27/-10

x=-2+7/10

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