-32-8m=-8m(2m-1)

Solution for -32-8m=-8m(2m-1) equation:

-32-8m=-8m(2m-1)

We move all terms to the left:

-32-8m-(-8m(2m-1))=0


We calculate terms in parentheses: -(-8m(2m-1)), so:

-8m(2m-1)

We multiply parentheses

-16m^2+8m

Back to the equation:

-(-16m^2+8m)


We get rid of parentheses

16m^2-8m-8m-32=0

We add all the numbers together, and all the variables

16m^2-16m-32=0

a = 16; b = -16; c = -32;
Δ = b2-4ac
Δ = -162-4·16·(-32)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-48}{2*16}=\frac{-32}{32}
=-1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+48}{2*16}=\frac{64}{32}
=2
$