-32-2v=-2(1+6v)

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Solution for -32-2v=-2(1+6v) equation: 



-32-2v=-2(1+6v)

We move all terms to the left:

-32-2v-(-2(1+6v))=0

We add all the numbers together, and all the variables

-2v-(-2(6v+1))-32=0



We calculate terms in parentheses: -(-2(6v+1)), so:

-2(6v+1)

We multiply parentheses

-12v-2

Back to the equation:

-(-12v-2)



We get rid of parentheses

-2v+12v+2-32=0

We add all the numbers together, and all the variables

10v-30=0

We move all terms containing v to the left, all other terms to the right

10v=30

v=30/10

v=3

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