-32-10n=13-5(n-5)

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Solution for -32-10n=13-5(n-5) equation: 



-32-10n=13-5(n-5)

We move all terms to the left:

-32-10n-(13-5(n-5))=0



We calculate terms in parentheses: -(13-5(n-5)), so:

13-5(n-5)

determiningTheFunctionDomain
-5(n-5)+13

We multiply parentheses

-5n+25+13

We add all the numbers together, and all the variables

-5n+38

Back to the equation:

-(-5n+38)



We get rid of parentheses

-10n+5n-38-32=0

We add all the numbers together, and all the variables

-5n-70=0

We move all terms containing n to the left, all other terms to the right

-5n=70

n=70/-5

n=-14

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