-31=2(x+3)-5(x-1)

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Solution for -31=2(x+3)-5(x-1) equation: 



-31=2(x+3)-5(x-1)

We move all terms to the left:

-31-(2(x+3)-5(x-1))=0



We calculate terms in parentheses: -(2(x+3)-5(x-1)), so:

2(x+3)-5(x-1)

We multiply parentheses

2x-5x+6+5

We add all the numbers together, and all the variables

-3x+11

Back to the equation:

-(-3x+11)



We get rid of parentheses

3x-11-31=0

We add all the numbers together, and all the variables

3x-42=0

We move all terms containing x to the left, all other terms to the right

3x=42

x=42/3

x=14

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