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-31-3x=5-5(1+5x)
We move all terms to the left:
-31-3x-(5-5(1+5x))=0
We add all the numbers together, and all the variables
-3x-(5-5(5x+1))-31=0
We calculate terms in parentheses: -(5-5(5x+1)), so:We get rid of parentheses
5-5(5x+1)
determiningTheFunctionDomain -5(5x+1)+5
We multiply parentheses
-25x-5+5
We add all the numbers together, and all the variables
-25x
Back to the equation:
-(-25x)
-3x+25x-31=0
We add all the numbers together, and all the variables
22x-31=0
We move all terms containing x to the left, all other terms to the right
22x=31
x=31/22
x=1+9/22
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