-31+13y+6=5(3y-2)-5

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Solution for -31+13y+6=5(3y-2)-5 equation: 



-31+13y+6=5(3y-2)-5

We move all terms to the left:

-31+13y+6-(5(3y-2)-5)=0

We add all the numbers together, and all the variables

13y-(5(3y-2)-5)-25=0



We calculate terms in parentheses: -(5(3y-2)-5), so:

5(3y-2)-5

We multiply parentheses

15y-10-5

We add all the numbers together, and all the variables

15y-15

Back to the equation:

-(15y-15)



We get rid of parentheses

13y-15y+15-25=0

We add all the numbers together, and all the variables

-2y-10=0

We move all terms containing y to the left, all other terms to the right

-2y=10

y=10/-2

y=-5

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