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-30=5(x-9)x=
We move all terms to the left:
-30-(5(x-9)x)=0
We calculate terms in parentheses: -(5(x-9)x), so:We get rid of parentheses
5(x-9)x
We multiply parentheses
5x^2-45x
Back to the equation:
-(5x^2-45x)
-5x^2+45x-30=0
a = -5; b = 45; c = -30;
Δ = b2-4ac
Δ = 452-4·(-5)·(-30)
Δ = 1425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1425}=\sqrt{25*57}=\sqrt{25}*\sqrt{57}=5\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-5\sqrt{57}}{2*-5}=\frac{-45-5\sqrt{57}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+5\sqrt{57}}{2*-5}=\frac{-45+5\sqrt{57}}{-10} $
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