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-30-5a=5+5(a-3)
We move all terms to the left:
-30-5a-(5+5(a-3))=0
We calculate terms in parentheses: -(5+5(a-3)), so:We get rid of parentheses
5+5(a-3)
determiningTheFunctionDomain 5(a-3)+5
We multiply parentheses
5a-15+5
We add all the numbers together, and all the variables
5a-10
Back to the equation:
-(5a-10)
-5a-5a+10-30=0
We add all the numbers together, and all the variables
-10a-20=0
We move all terms containing a to the left, all other terms to the right
-10a=20
a=20/-10
a=-2
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