-3/x=-9/3x+3

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Solution for -3/x=-9/3x+3 equation: 



-3/x=-9/3x+3

We move all terms to the left:

-3/x-(-9/3x+3)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 3x+3)!=0

x∈R



We get rid of parentheses

-3/x+9/3x-3=0

We calculate fractions


(-9x)/3x^2+9x/3x^2-3=0

We multiply all the terms by the denominator


(-9x)+9x-3*3x^2=0

We add all the numbers together, and all the variables

9x+(-9x)-3*3x^2=0

Wy multiply elements

-9x^2+9x+(-9x)=0

We get rid of parentheses

-9x^2+9x-9x=0

We add all the numbers together, and all the variables

-9x^2=0

a = -9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-9)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-18}=0$

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