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-3/x+1=x-5/x-5
We move all terms to the left:
-3/x+1-(x-5/x-5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x-5)!=0We get rid of parentheses
x∈R
-3/x-x+5/x+5+1=0
We multiply all the terms by the denominator
-x*x+5*x+1*x-3+5=0
We add all the numbers together, and all the variables
6x-x*x+2=0
Wy multiply elements
-1x^2+6x+2=0
a = -1; b = 6; c = +2;
Δ = b2-4ac
Δ = 62-4·(-1)·2
Δ = 44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{44}=\sqrt{4*11}=\sqrt{4}*\sqrt{11}=2\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{11}}{2*-1}=\frac{-6-2\sqrt{11}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{11}}{2*-1}=\frac{-6+2\sqrt{11}}{-2} $
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