-3/5x=-25x=35

Solution for -3/5x=-25x=35 equation:

-3/5x=-25x=35

We move all terms to the left:

-3/5x-(-25x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We get rid of parentheses

-3/5x+25x=0

We multiply all the terms by the denominator


25x*5x-3=0

Wy multiply elements

125x^2-3=0

a = 125; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·125·(-3)
Δ = 1500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1500}=\sqrt{100*15}=\sqrt{100}*\sqrt{15}=10\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{15}}{2*125}=\frac{0-10\sqrt{15}}{250}
=-\frac{10\sqrt{15}}{250}
=-\frac{\sqrt{15}}{25}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{15}}{2*125}=\frac{0+10\sqrt{15}}{250}
=\frac{10\sqrt{15}}{250}
=\frac{\sqrt{15}}{25}
$