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-3/5x-3=-6x+24
We move all terms to the left:
-3/5x-3-(-6x+24)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
-3/5x+6x-24-3=0
We multiply all the terms by the denominator
6x*5x-24*5x-3*5x-3=0
Wy multiply elements
30x^2-120x-15x-3=0
We add all the numbers together, and all the variables
30x^2-135x-3=0
a = 30; b = -135; c = -3;
Δ = b2-4ac
Δ = -1352-4·30·(-3)
Δ = 18585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18585}=\sqrt{9*2065}=\sqrt{9}*\sqrt{2065}=3\sqrt{2065}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-135)-3\sqrt{2065}}{2*30}=\frac{135-3\sqrt{2065}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-135)+3\sqrt{2065}}{2*30}=\frac{135+3\sqrt{2065}}{60} $
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