-3/5=5-4c/3c+10

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Solution for -3/5=5-4c/3c+10 equation: 



-3/5=5-4c/3c+10

We move all terms to the left:

-3/5-(5-4c/3c+10)=0



Domain of the equation: 3c+10)!=0

c∈R



We add all the numbers together, and all the variables

-(-4c/3c+15)-3/5=0

We get rid of parentheses

4c/3c-15-3/5=0

We calculate fractions


20c/15c+(-9c)/15c-15=0

We multiply all the terms by the denominator


20c+(-9c)-15*15c=0

Wy multiply elements

20c+(-9c)-225c=0

We get rid of parentheses

20c-9c-225c=0

We add all the numbers together, and all the variables

-214c=0

c=0/-214

c=0

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