-3/5(20x+15)=1/10(20x-90)

Solution for -3/5(20x+15)=1/10(20x-90) equation:

-3/5(20x+15)=1/10(20x-90)

We move all terms to the left:

-3/5(20x+15)-(1/10(20x-90))=0


Domain of the equation: 5(20x+15)!=0

x∈R



Domain of the equation: 10(20x-90))!=0

x∈R


We calculate fractions


(-30x2/(5(20x+15)*10(20x-90)))+(-5x2/(5(20x+15)*10(20x-90)))=0


We calculate terms in parentheses: +(-30x2/(5(20x+15)*10(20x-90))), so:

-30x2/(5(20x+15)*10(20x-90))

We multiply all the terms by the denominator


-30x2

We add all the numbers together, and all the variables

-30x^2

Back to the equation:

+(-30x^2)



We calculate terms in parentheses: +(-5x2/(5(20x+15)*10(20x-90))), so:

-5x2/(5(20x+15)*10(20x-90))

We multiply all the terms by the denominator


-5x2

We add all the numbers together, and all the variables

-5x^2

Back to the equation:

+(-5x^2)


We get rid of parentheses

-30x^2-5x^2=0

We add all the numbers together, and all the variables

-35x^2=0

a = -35; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-35)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-70}=0$