-3/4x2+8=0

Solution for -3/4x2+8=0 equation:

-3/4x^2+8=0


Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


8*4x^2-3=0

Wy multiply elements

32x^2-3=0

a = 32; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·32·(-3)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*32}=\frac{0-8\sqrt{6}}{64}
=-\frac{8\sqrt{6}}{64}
=-\frac{\sqrt{6}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*32}=\frac{0+8\sqrt{6}}{64}
=\frac{8\sqrt{6}}{64}
=\frac{\sqrt{6}}{8}
$