-3/4+2/5x=7/20x=1/2

Solution for -3/4+2/5x=7/20x=1/2 equation:

-3/4+2/5x=7/20x=1/2

We move all terms to the left:

-3/4+2/5x-(7/20x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 20x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/5x-(+7/20x)-3/4=0

We get rid of parentheses

2/5x-7/20x-3/4=0

We calculate fractions


(-600x^2)/1600x^2+640x/1600x^2+(-560x)/1600x^2=0

We multiply all the terms by the denominator


(-600x^2)+640x+(-560x)=0

We get rid of parentheses

-600x^2+640x-560x=0

We add all the numbers together, and all the variables

-600x^2+80x=0

a = -600; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·(-600)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*-600}=\frac{-160}{-1200}
=2/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*-600}=\frac{0}{-1200}
=0
$