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-3/4+2/5x=7/20x=-1/2
We move all terms to the left:
-3/4+2/5x-(7/20x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 20x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/5x-(+7/20x)-3/4=0
We get rid of parentheses
2/5x-7/20x-3/4=0
We calculate fractions
(-600x^2)/1600x^2+640x/1600x^2+(-560x)/1600x^2=0
We multiply all the terms by the denominator
(-600x^2)+640x+(-560x)=0
We get rid of parentheses
-600x^2+640x-560x=0
We add all the numbers together, and all the variables
-600x^2+80x=0
a = -600; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·(-600)·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*-600}=\frac{-160}{-1200} =2/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*-600}=\frac{0}{-1200} =0 $
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