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-3/4(12-8x)+4x=x-18
We move all terms to the left:
-3/4(12-8x)+4x-(x-18)=0
Domain of the equation: 4(12-8x)!=0We add all the numbers together, and all the variables
x∈R
-3/4(-8x+12)+4x-(x-18)=0
We add all the numbers together, and all the variables
4x-3/4(-8x+12)-(x-18)=0
We get rid of parentheses
4x-3/4(-8x+12)-x+18=0
We multiply all the terms by the denominator
4x*4(-8x+12)-x*4(-8x+12)+18*4(-8x+12)-3=0
Wy multiply elements
16x^2(--4x^2(-+72x(--3=0
We use the square of the difference formula
16x^2(+4x^2(-72x(+3=0
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