-3/2=(k+3)/(-3k-3)

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Solution for -3/2=(k+3)/(-3k-3) equation:



-3/2=(k+3)/(-3k-3)
We move all terms to the left:
-3/2-((k+3)/(-3k-3))=0
Domain of the equation: (-3k-3))!=0
k∈R
We calculate fractions
(-((k+3)*2)/(-6k)+9k/(-6k)=0
We calculate terms in parentheses: +(-((k+3)*2)/(-6k)+9k/(-6k), so:
-((k+3)*2)/(-6k)+9k/(-6k
We calculate fractions
(-((k+3)*2)*(-6k)/((-6k)*(-6k)+(-54k^2)/((-6k)*(-6k)
We calculate terms in parentheses: +(-((k+3)*2)*(-6k)/((-6k)*(-6k)+(-54k^2)/((-6k)*(-6k), so:
-((k+3)*2)*(-6k)/((-6k)*(-6k)+(-54k^2)/((-6k)*(-6k
We can not solve this equation

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