-3/2(4b-8)=-6

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Solution for -3/2(4b-8)=-6 equation: 



-3/2(4b-8)=-6

We move all terms to the left:

-3/2(4b-8)-(-6)=0



Domain of the equation: 2(4b-8)!=0

b∈R



We add all the numbers together, and all the variables

-3/2(4b-8)+6=0

We multiply all the terms by the denominator


6*2(4b-8)-3=0

Wy multiply elements

12b(4-3=0

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