-3/2(3/4*b+2)=-5/2+3/5*b

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Solution for -3/2(3/4*b+2)=-5/2+3/5*b equation: 


b in (-oo:+oo)

(-3/2)*((3/4)*b+2) = (3/5)*b-5/2 // - (3/5)*b-5/2

(-3/2)*((3/4)*b+2)-((3/5)*b)-(-5/2) = 0

(-3/2)*((3/4)*b+2)+(-3/5)*b+5/2 = 0

(-3*b)/5-3/2*(3/4*b+2)+5/2 = 0

(-3/2*2*5*(3/4*b+2))/(2*5)+(-3*2*b)/(2*5)+(5^2)/(2*5) = 0

25-3/2*2*5*(3/4*b+2)-3*2*b = 0

25-69/4*b-30 = 0

-69/4*b-5 = 0

(-69/4*b-5)/(2*5) = 0

(-69/4*b-5)/(2*5) = 0 // * 2*5

-69/4*b-5 = 0

-69/4*b-5 = 0 // + 5

-69/4*b = 5 // : -69/4

b = 5/(-69/4)

b = -20/69

b = -20/69

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