-3-7(x+2)=-8(1+x)8x

Solution for -3-7(x+2)=-8(1+x)8x equation:

-3-7(x+2)=-8(1+x)8x

We move all terms to the left:

-3-7(x+2)-(-8(1+x)8x)=0

We add all the numbers together, and all the variables

-7(x+2)-(-8(x+1)8x)-3=0

We multiply parentheses

-7x-(-8(x+1)8x)-14-3=0


We calculate terms in parentheses: -(-8(x+1)8x), so:

-8(x+1)8x

We multiply parentheses

-64x^2-64x

Back to the equation:

-(-64x^2-64x)


We add all the numbers together, and all the variables

-(-64x^2-64x)-7x-17=0

We get rid of parentheses

64x^2+64x-7x-17=0

We add all the numbers together, and all the variables

64x^2+57x-17=0

a = 64; b = 57; c = -17;
Δ = b2-4ac
Δ = 572-4·64·(-17)
Δ = 7601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-\sqrt{7601}}{2*64}=\frac{-57-\sqrt{7601}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+\sqrt{7601}}{2*64}=\frac{-57+\sqrt{7601}}{128}
$