-3-3(a+1)=3(a+2)

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Solution for -3-3(a+1)=3(a+2) equation:



-3-3(a+1)=3(a+2)
We move all terms to the left:
-3-3(a+1)-(3(a+2))=0
We multiply parentheses
-3a-(3(a+2))-3-3=0
We calculate terms in parentheses: -(3(a+2)), so:
3(a+2)
We multiply parentheses
3a+6
Back to the equation:
-(3a+6)
We add all the numbers together, and all the variables
-3a-(3a+6)-6=0
We get rid of parentheses
-3a-3a-6-6=0
We add all the numbers together, and all the variables
-6a-12=0
We move all terms containing a to the left, all other terms to the right
-6a=12
a=12/-6
a=-2

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