-3+2x-(3-5x-4x+3)=8(4+2x)

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Solution for -3+2x-(3-5x-4x+3)=8(4+2x) equation: 



-3+2x-(3-5x-4x+3)=8(4+2x)

We move all terms to the left:

-3+2x-(3-5x-4x+3)-(8(4+2x))=0

We add all the numbers together, and all the variables

2x-(-9x+6)-(8(2x+4))-3=0

We get rid of parentheses

2x+9x-(8(2x+4))-6-3=0



We calculate terms in parentheses: -(8(2x+4)), so:

8(2x+4)

We multiply parentheses

16x+32

Back to the equation:

-(16x+32)



We add all the numbers together, and all the variables

11x-(16x+32)-9=0

We get rid of parentheses

11x-16x-32-9=0

We add all the numbers together, and all the variables

-5x-41=0

We move all terms containing x to the left, all other terms to the right

-5x=41

x=41/-5

x=-8+1/5

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